How much printed linear resolution do you need to support optimal viewing from various distance? I think I assumed a maximum resolving power of 1 minute of arc (MOA), so we want each pixel to subtend 1 MOA at the chosen viewing distance. First, for a viewing distance of about 50cm (0.5m): {{{ x/50cm == tan(0.000145444) x/50cm == 0.000145444 x = 0.0072722 cm 2x = 0.0145444 cm (base of triangle, and the length subtended at 50cm == 0.145444 mm == 175 dpi for viewing at 50cm }}} For further confirmation, the page on [[http://en.wikipedia.org/wiki/Minute_of_arc#Firearms| MOA for firearms]] states 1MOA at 100m distance is 29.08mm. A simple linear scaling confirms that this is correct. What's a simpler formula for ready reckoning? {{{ 2.54 / (A_CONST * 2 * VIEWING DISTANCE IN CM) From left to right: 2.54 / 0.000145444 / 2 / VIEWING DISTANCE }}} This we arrive at: * 218 dpi at 40cm * 291 dpi at 30cm * 436 dpi at 20cm The constant is: 8,731.883061522 '''8732 / VIEWING DISTANCE == necessary DPI''' You could round this to: '''9000 / VIEWING_DISTANCE_IN_CM = necessary DPI''' || Distance || Necessary linear resolution || Nearest useful number? || || 10m || 9 dpi || 10 dpi || || 5m || 18 dpi || 20 dpi || || 3m || 29 dpi || 30 dpi || || 1m || 87 dpi || 90 dpi || || 50cm || 175 dpi || 180 dpi || || 40cm || 218 dpi || 225 dpi || || 30cm || 291 dpi || 300 dpi || || 20cm || 436 dpi || 450 dpi || || 10cm || 872 dpi || 900 dpi || I dunno if these longer distances hold up to scrutiny - are they correct? They'd suggest that long-distance roadside billboards can be comfortably printed with lolhueg pixels that are like 4.36mm in diameter.